14243110234433 has 4 divisors (see below), whose sum is σ = 14574345356208. Its totient is φ = 13911875112660.

The previous prime is 14243110234399. The next prime is 14243110234439. The reversal of 14243110234433 is 33443201134241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14243110234433 - 2³⁰ = 14242036492609 is a prime.

It is a super-3 number, since 3×14243110234433³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14243110234393 and 14243110234402.

It is not an unprimeable number, because it can be changed into a prime (14243110234439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165617560823 + ... + 165617560908.

It is an arithmetic number, because the mean of its divisors is an integer number (3643586339052).

Almost surely, 2^{14243110234433} is an apocalyptic number.

It is an amenable number.

14243110234433 is a deficient number, since it is larger than the sum of its proper divisors (331235121775).

14243110234433 is an equidigital number, since it uses as much as digits as its factorization.

14243110234433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 331235121774.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 14243110234433 its reverse (33443201134241), we get a palindrome (47686311368674).

The spelling of 14243110234433 in words is "fourteen trillion, two hundred forty-three billion, one hundred ten million, two hundred thirty-four thousand, four hundred thirty-three".