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142433003443 = 152699328247
BaseRepresentation
bin1000010010100110101…
…0110010011110110011
3111121122101211021000211
42010221222302132303
54313200322102233
6145233253324551
713201423360543
oct2045152623663
9447571737024
10142433003443
1155450798695
1223730636757
131057b9649c3
146c727dd323
153a896165cd
hex2129ab27b3

142433003443 has 4 divisors (see below), whose sum is σ = 142442346960. Its totient is φ = 142423659928.

The previous prime is 142433003431. The next prime is 142433003459. The reversal of 142433003443 is 344300334241.

142433003443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142433003443 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142433003423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4648855 + ... + 4679392.

It is an arithmetic number, because the mean of its divisors is an integer number (35610586740).

Almost surely, 2142433003443 is an apocalyptic number.

142433003443 is a deficient number, since it is larger than the sum of its proper divisors (9343517).

142433003443 is an equidigital number, since it uses as much as digits as its factorization.

142433003443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9343516.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 142433003443 its reverse (344300334241), we get a palindrome (486733337684).

The spelling of 142433003443 in words is "one hundred forty-two billion, four hundred thirty-three million, three thousand, four hundred forty-three".

Divisors: 1 15269 9328247 142433003443