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14244040333443 = 312811337061137
BaseRepresentation
bin1100111101000111001011…
…1101101101100010000011
31212102201100122212101021210
43033101302331231202003
53331333243311132233
650143342150221203
73000045412066134
oct317216275554203
955381318771253
1014244040333443
1145a1955477178
121720710354803
137c42903c960b
143735b556dc8b
1519a7c08ea163
hexcf472f6d883

14244040333443 has 8 divisors (see below), whose sum is σ = 18992202534928. Its totient is φ = 9495952510464.

The previous prime is 14244040333363. The next prime is 14244040333447. The reversal of 14244040333443 is 34433304044241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14244040333443 - 216 = 14244040267907 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14244040333447) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18146230 + ... + 18914907.

It is an arithmetic number, because the mean of its divisors is an integer number (2374025316866).

Almost surely, 214244040333443 is an apocalyptic number.

14244040333443 is a deficient number, since it is larger than the sum of its proper divisors (4748162201485).

14244040333443 is a wasteful number, since it uses less digits than its factorization.

14244040333443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37189253.

The product of its (nonzero) digits is 663552, while the sum is 39.

Adding to 14244040333443 its reverse (34433304044241), we get a palindrome (48677344377684).

The spelling of 14244040333443 in words is "fourteen trillion, two hundred forty-four billion, forty million, three hundred thirty-three thousand, four hundred forty-three".

Divisors: 1 3 128113 384339 37061137 111183411 4748013444481 14244040333443