Base | Representation |
---|---|
bin | 1000010010101000110… |
… | …1001110010000100001 |
3 | 111121200000210212021221 |
4 | 2010222031032100201 |
5 | 4313210124430423 |
6 | 145234215015041 |
7 | 13201563164425 |
oct | 2045215162041 |
9 | 447600725257 |
10 | 142442030113 |
11 | 554558a3549 |
12 | 2373366a481 |
13 | 105807a5526 |
14 | 6c73aacb85 |
15 | 3a8a2eae5d |
hex | 212a34e421 |
142442030113 has 2 divisors, whose sum is σ = 142442030114. Its totient is φ = 142442030112.
The previous prime is 142442030057. The next prime is 142442030209. The reversal of 142442030113 is 311030244241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 121516382464 + 20925647649 = 348592^2 + 144657^2 .
It is a cyclic number.
It is not a de Polignac number, because 142442030113 - 225 = 142408475681 is a prime.
It is not a weakly prime, because it can be changed into another prime (142442030413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71221015056 + 71221015057.
It is an arithmetic number, because the mean of its divisors is an integer number (71221015057).
Almost surely, 2142442030113 is an apocalyptic number.
It is an amenable number.
142442030113 is a deficient number, since it is larger than the sum of its proper divisors (1).
142442030113 is an equidigital number, since it uses as much as digits as its factorization.
142442030113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 142442030113 its reverse (311030244241), we get a palindrome (453472274354).
The spelling of 142442030113 in words is "one hundred forty-two billion, four hundred forty-two million, thirty thousand, one hundred thirteen".
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