Search a number
-
+
14244340003 = 43331263721
BaseRepresentation
bin11010100010000011…
…10110000100100011
31100202201020110001021
431101001312010203
5213133022340003
610313241350311
71012662615025
oct152101660443
940681213037
1014244340003
11604a616523
122916498397
13146011c26a
14991b1c015
155857ea2bd
hex351076123

14244340003 has 4 divisors (see below), whose sum is σ = 14575603768. Its totient is φ = 13913076240.

The previous prime is 14244339959. The next prime is 14244340037. The reversal of 14244340003 is 30004344241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30004344241 = 47638390303.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14244340003 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14244340003.

It is not an unprimeable number, because it can be changed into a prime (14244340043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165631818 + ... + 165631903.

It is an arithmetic number, because the mean of its divisors is an integer number (3643900942).

Almost surely, 214244340003 is an apocalyptic number.

14244340003 is a deficient number, since it is larger than the sum of its proper divisors (331263765).

14244340003 is an equidigital number, since it uses as much as digits as its factorization.

14244340003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 331263764.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 14244340003 its reverse (30004344241), we get a palindrome (44248684244).

The spelling of 14244340003 in words is "fourteen billion, two hundred forty-four million, three hundred forty thousand, three".

Divisors: 1 43 331263721 14244340003