Base | Representation |
---|---|
bin | 1000010010101010110… |
… | …0110001101001100001 |
3 | 111121200121101002112222 |
4 | 2010222230301221201 |
5 | 4313214234122122 |
6 | 145235112200425 |
7 | 13202023404365 |
oct | 2045254615141 |
9 | 447617332488 |
10 | 142450301537 |
11 | 5545a532a35 |
12 | 23736399115 |
13 | 1058241036b |
14 | 6c74c232a5 |
15 | 3a8add1b42 |
hex | 212ab31a61 |
142450301537 has 2 divisors, whose sum is σ = 142450301538. Its totient is φ = 142450301536.
The previous prime is 142450301509. The next prime is 142450301597. The reversal of 142450301537 is 735103054241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 138800208481 + 3650093056 = 372559^2 + 60416^2 .
It is a cyclic number.
It is not a de Polignac number, because 142450301537 - 226 = 142383192673 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 142450301497 and 142450301506.
It is not a weakly prime, because it can be changed into another prime (142450301597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71225150768 + 71225150769.
It is an arithmetic number, because the mean of its divisors is an integer number (71225150769).
Almost surely, 2142450301537 is an apocalyptic number.
It is an amenable number.
142450301537 is a deficient number, since it is larger than the sum of its proper divisors (1).
142450301537 is an equidigital number, since it uses as much as digits as its factorization.
142450301537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 35.
Adding to 142450301537 its reverse (735103054241), we get a palindrome (877553355778).
The spelling of 142450301537 in words is "one hundred forty-two billion, four hundred fifty million, three hundred one thousand, five hundred thirty-seven".
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