Base | Representation |
---|---|
bin | 11010100010001001… |
… | …11001101000101001 |
3 | 1100202202202010212001 |
4 | 31101010321220221 |
5 | 213133224003113 |
6 | 10313310451001 |
7 | 1013002462264 |
oct | 152104715051 |
9 | 40682663761 |
10 | 14245141033 |
11 | 6050013332 |
12 | 2916803a61 |
13 | 146033ca46 |
14 | 991c89cdb |
15 | 5859077dd |
hex | 351139a29 |
14245141033 has 2 divisors, whose sum is σ = 14245141034. Its totient is φ = 14245141032.
The previous prime is 14245140979. The next prime is 14245141067. The reversal of 14245141033 is 33014154241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7626179584 + 6618961449 = 87328^2 + 81357^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14245141033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14245140992 and 14245141010.
It is not a weakly prime, because it can be changed into another prime (14245141733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7122570516 + 7122570517.
It is an arithmetic number, because the mean of its divisors is an integer number (7122570517).
Almost surely, 214245141033 is an apocalyptic number.
It is an amenable number.
14245141033 is a deficient number, since it is larger than the sum of its proper divisors (1).
14245141033 is an equidigital number, since it uses as much as digits as its factorization.
14245141033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 14245141033 its reverse (33014154241), we get a palindrome (47259295274).
The spelling of 14245141033 in words is "fourteen billion, two hundred forty-five million, one hundred forty-one thousand, thirty-three".
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