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14245444434673 is a prime number
BaseRepresentation
bin1100111101001100011010…
…1001111011101011110001
31212102211222111221010002001
43033103012221323223301
53331344132233402143
650144133345054001
73000125251542544
oct317230651735361
955384874833061
1014245444434673
1145a2506007211
121720a42627301
137c4455282a4a
143736a9c2c85b
1519a853d0014d
hexcf4c6a7baf1

14245444434673 has 2 divisors, whose sum is σ = 14245444434674. Its totient is φ = 14245444434672.

The previous prime is 14245444434593. The next prime is 14245444434691. The reversal of 14245444434673 is 37643444454241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13243026975409 + 1002417459264 = 3639097^2 + 1001208^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14245444434673 is a prime.

It is not a weakly prime, because it can be changed into another prime (14245444434173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7122722217336 + 7122722217337.

It is an arithmetic number, because the mean of its divisors is an integer number (7122722217337).

Almost surely, 214245444434673 is an apocalyptic number.

It is an amenable number.

14245444434673 is a deficient number, since it is larger than the sum of its proper divisors (1).

14245444434673 is an equidigital number, since it uses as much as digits as its factorization.

14245444434673 is an evil number, because the sum of its binary digits is even.

The product of its digits is 61931520, while the sum is 55.

The spelling of 14245444434673 in words is "fourteen trillion, two hundred forty-five billion, four hundred forty-four million, four hundred thirty-four thousand, six hundred seventy-three".