Search a number
-
+
1425103460234 = 2712551730117
BaseRepresentation
bin10100101111001110110…
…010010001011110001010
312001020102220120201001022
4110233032302101132022
5141322102441211414
63010403344552442
7204650251354526
oct24571662213612
95036386521038
101425103460234
114aa423829543
121b0240322722
13a45046c5b5c
144cd92604d86
152710be6c18e
hex14bcec9178a

1425103460234 has 4 divisors (see below), whose sum is σ = 2137655190354. Its totient is φ = 712551730116.

The previous prime is 1425103460201. The next prime is 1425103460239. The reversal of 1425103460234 is 4320643015241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1403786584225 + 21316876009 = 1184815^2 + 146003^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1425103460194 and 1425103460203.

It is not an unprimeable number, because it can be changed into a prime (1425103460239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 356275865057 + ... + 356275865060.

Almost surely, 21425103460234 is an apocalyptic number.

1425103460234 is a deficient number, since it is larger than the sum of its proper divisors (712551730120).

1425103460234 is an equidigital number, since it uses as much as digits as its factorization.

1425103460234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 712551730119.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 1425103460234 its reverse (4320643015241), we get a palindrome (5745746475475).

The spelling of 1425103460234 in words is "one trillion, four hundred twenty-five billion, one hundred three million, four hundred sixty thousand, two hundred thirty-four".

Divisors: 1 2 712551730117 1425103460234