Base | Representation |
---|---|
bin | 10100101111001111010… |
… | …111100000001101010011 |
3 | 12001020110120221112211021 |
4 | 110233033113200031103 |
5 | 141322112441014143 |
6 | 3010404334100311 |
7 | 204650430333451 |
oct | 24571727401523 |
9 | 5036416845737 |
10 | 1425113219923 |
11 | 4aa4292950a8 |
12 | 1b024364a697 |
13 | a4506732213 |
14 | 4cd93a259d1 |
15 | 2710cc48ced |
hex | 14bcf5e0353 |
1425113219923 has 2 divisors, whose sum is σ = 1425113219924. Its totient is φ = 1425113219922.
The previous prime is 1425113219911. The next prime is 1425113219947. The reversal of 1425113219923 is 3299123115241.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1425113219923 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1425113219923.
It is not a weakly prime, because it can be changed into another prime (1425113289923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712556609961 + 712556609962.
It is an arithmetic number, because the mean of its divisors is an integer number (712556609962).
Almost surely, 21425113219923 is an apocalyptic number.
1425113219923 is a deficient number, since it is larger than the sum of its proper divisors (1).
1425113219923 is an equidigital number, since it uses as much as digits as its factorization.
1425113219923 is an evil number, because the sum of its binary digits is even.
The product of its digits is 116640, while the sum is 43.
The spelling of 1425113219923 in words is "one trillion, four hundred twenty-five billion, one hundred thirteen million, two hundred nineteen thousand, nine hundred twenty-three".
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