Base | Representation |
---|---|
bin | 11010100010111000… |
… | …10010010101000011 |
3 | 1100210012021121021001 |
4 | 31101130102111003 |
5 | 213141311141431 |
6 | 10314050112431 |
7 | 1013105544322 |
oct | 152134222503 |
9 | 40705247231 |
10 | 14251271491 |
11 | 6053520226 |
12 | 291887b717 |
13 | 14616a8232 |
14 | 992a040b9 |
15 | 586218e61 |
hex | 351712543 |
14251271491 has 2 divisors, whose sum is σ = 14251271492. Its totient is φ = 14251271490.
The previous prime is 14251271453. The next prime is 14251271497. The reversal of 14251271491 is 19417215241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14251271491 - 211 = 14251269443 is a prime.
It is a super-2 number, since 2×142512714912 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14251271491.
It is not a weakly prime, because it can be changed into another prime (14251271497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7125635745 + 7125635746.
It is an arithmetic number, because the mean of its divisors is an integer number (7125635746).
Almost surely, 214251271491 is an apocalyptic number.
14251271491 is a deficient number, since it is larger than the sum of its proper divisors (1).
14251271491 is an equidigital number, since it uses as much as digits as its factorization.
14251271491 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20160, while the sum is 37.
The spelling of 14251271491 in words is "fourteen billion, two hundred fifty-one million, two hundred seventy-one thousand, four hundred ninety-one".
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