Base | Representation |
---|---|
bin | 1100111101100101010000… |
… | …0010111011000010110010 |
3 | 1212110111012011021011202212 |
4 | 3033121110002323002302 |
5 | 3332001311023243102 |
6 | 50151155112212122 |
7 | 3000452416160561 |
oct | 317312402730262 |
9 | 55414164234685 |
10 | 14252111540402 |
11 | 45a531745a44a |
12 | 17221a339a042 |
13 | 7c4c78611718 |
14 | 373b3d491bd8 |
15 | 19aae42adc52 |
hex | cf6540bb0b2 |
14252111540402 has 4 divisors (see below), whose sum is σ = 21378167310606. Its totient is φ = 7126055770200.
The previous prime is 14252111540383. The next prime is 14252111540411. The reversal of 14252111540402 is 20404511125241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7810510183441 + 6441601356961 = 2794729^2 + 2538031^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3563027885099 + ... + 3563027885102.
Almost surely, 214252111540402 is an apocalyptic number.
14252111540402 is a deficient number, since it is larger than the sum of its proper divisors (7126055770204).
14252111540402 is an equidigital number, since it uses as much as digits as its factorization.
14252111540402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7126055770203.
The product of its (nonzero) digits is 12800, while the sum is 32.
Adding to 14252111540402 its reverse (20404511125241), we get a palindrome (34656622665643).
The spelling of 14252111540402 in words is "fourteen trillion, two hundred fifty-two billion, one hundred eleven million, five hundred forty thousand, four hundred two".
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