Base | Representation |
---|---|
bin | 100000011001111110011100… |
… | …011111010111000111010011 |
3 | 200200122000112211112100211102 |
4 | 200121332130133113013103 |
5 | 122140042112431000003 |
6 | 1223041535541335015 |
7 | 42006625016112353 |
oct | 4031763437270723 |
9 | 620560484470742 |
10 | 142522525250003 |
11 | 41459510a49218 |
12 | 13b999a140746b |
13 | 616aa7c9ca822 |
14 | 272a1ac7cab63 |
15 | 11725108d0588 |
hex | 819f9c7d71d3 |
142522525250003 has 4 divisors (see below), whose sum is σ = 147437095086240. Its totient is φ = 137607955413768.
The previous prime is 142522525249981. The next prime is 142522525250047. The reversal of 142522525250003 is 300052525225241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 142522525250003 - 224 = 142522508472787 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (142522525250093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2457284918075 + ... + 2457284918132.
It is an arithmetic number, because the mean of its divisors is an integer number (36859273771560).
Almost surely, 2142522525250003 is an apocalyptic number.
142522525250003 is a deficient number, since it is larger than the sum of its proper divisors (4914569836237).
142522525250003 is an equidigital number, since it uses as much as digits as its factorization.
142522525250003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4914569836236.
The product of its (nonzero) digits is 240000, while the sum is 38.
The spelling of 142522525250003 in words is "one hundred forty-two trillion, five hundred twenty-two billion, five hundred twenty-five million, two hundred fifty thousand, three".
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