142523521250041 has 4 divisors (see below), whose sum is σ = 145838021744272. Its totient is φ = 139209020755812.

The previous prime is 142523521249979. The next prime is 142523521250053. The reversal of 142523521250041 is 140052125325241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142523521250041 - 2⁴¹ = 140324497994489 is a prime.

It is a super-4 number, since 4×142523521250041⁴ (a number of 58 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142523521250141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1657250247051 + ... + 1657250247136.

It is an arithmetic number, because the mean of its divisors is an integer number (36459505436068).

Almost surely, 2^{142523521250041} is an apocalyptic number.

It is an amenable number.

142523521250041 is a deficient number, since it is larger than the sum of its proper divisors (3314500494231).

142523521250041 is an equidigital number, since it uses as much as digits as its factorization.

142523521250041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3314500494230.

The product of its (nonzero) digits is 96000, while the sum is 37.

Adding to 142523521250041 its reverse (140052125325241), we get a palindrome (282575646575282).

The spelling of 142523521250041 in words is "one hundred forty-two trillion, five hundred twenty-three billion, five hundred twenty-one million, two hundred fifty thousand, forty-one".