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14254000433 is a prime number
BaseRepresentation
bin11010100011001101…
…01100100100110001
31100210101102020122222
431101212230210301
5213143011003213
610314224410425
71013141001401
oct152146544461
940711366588
1014254000433
116055014552
122919776a15
1314621223aa
14993114801
155865a7808
hex3519ac931

14254000433 has 2 divisors, whose sum is σ = 14254000434. Its totient is φ = 14254000432.

The previous prime is 14254000429. The next prime is 14254000471. The reversal of 14254000433 is 33400045241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11197237489 + 3056762944 = 105817^2 + 55288^2 .

It is an emirp because it is prime and its reverse (33400045241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14254000433 - 22 = 14254000429 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (14254000403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7127000216 + 7127000217.

It is an arithmetic number, because the mean of its divisors is an integer number (7127000217).

Almost surely, 214254000433 is an apocalyptic number.

It is an amenable number.

14254000433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14254000433 is an equidigital number, since it uses as much as digits as its factorization.

14254000433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 26.

Adding to 14254000433 its reverse (33400045241), we get a palindrome (47654045674).

The spelling of 14254000433 in words is "fourteen billion, two hundred fifty-four million, four hundred thirty-three", and thus it is an aban number.