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142544123203151 = 59113199107439947
BaseRepresentation
bin100000011010010010100011…
…110101000000111001001111
3200200201002022000220001201002
4200122102203311000321033
5122140420331020000101
61223055511032410515
742011321153512655
oct4032224365007117
9620632260801632
10142544123203151
114146769448107a
1213ba200a546a3b
13616cb12472667
14272b25add2dd5
151172d76a93d6b
hex81a4a3d40e4f

142544123203151 has 16 divisors (see below), whose sum is σ = 146977848864000. Its totient is φ = 138190118064768.

The previous prime is 142544123203147. The next prime is 142544123203159. The reversal of 142544123203151 is 151302321445241.

It is a cyclic number.

It is not a de Polignac number, because 142544123203151 - 22 = 142544123203147 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142544123203159) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52393241 + ... + 55046706.

It is an arithmetic number, because the mean of its divisors is an integer number (9186115554000).

Almost surely, 2142544123203151 is an apocalyptic number.

142544123203151 is a deficient number, since it is larger than the sum of its proper divisors (4433725660849).

142544123203151 is a wasteful number, since it uses less digits than its factorization.

142544123203151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107440318.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 142544123203151 its reverse (151302321445241), we get a palindrome (293846444648392).

The spelling of 142544123203151 in words is "one hundred forty-two trillion, five hundred forty-four billion, one hundred twenty-three million, two hundred three thousand, one hundred fifty-one".

Divisors: 1 59 113 199 6667 11741 22487 1326733 107439947 6338956873 12140714011 21380549453 716302126649 1261452417727 2416002088189 142544123203151