Base | Representation |
---|---|
bin | 11010100011010100… |
… | …10100001011011001 |
3 | 1100210110012102222002 |
4 | 31101222110023121 |
5 | 213143231332311 |
6 | 10314301010345 |
7 | 1013152032212 |
oct | 152152241331 |
9 | 40713172862 |
10 | 14254949081 |
11 | 605560225a |
12 | 2919b539b5 |
13 | 1462395119 |
14 | 9932c0409 |
15 | 5866e393b |
hex | 351a942d9 |
14254949081 has 2 divisors, whose sum is σ = 14254949082. Its totient is φ = 14254949080.
The previous prime is 14254949057. The next prime is 14254949117. The reversal of 14254949081 is 18094945241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13037985856 + 1216963225 = 114184^2 + 34885^2 .
It is a cyclic number.
It is not a de Polignac number, because 14254949081 - 214 = 14254932697 is a prime.
It is a super-2 number, since 2×142549490812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14254949281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7127474540 + 7127474541.
It is an arithmetic number, because the mean of its divisors is an integer number (7127474541).
Almost surely, 214254949081 is an apocalyptic number.
It is an amenable number.
14254949081 is a deficient number, since it is larger than the sum of its proper divisors (1).
14254949081 is an equidigital number, since it uses as much as digits as its factorization.
14254949081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 47.
The spelling of 14254949081 in words is "fourteen billion, two hundred fifty-four million, nine hundred forty-nine thousand, eighty-one".
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