Base | Representation |
---|---|
bin | 11010100011011111… |
… | …11011010100011001 |
3 | 1100210112222011212001 |
4 | 31101233323110121 |
5 | 213144120420441 |
6 | 10314352321001 |
7 | 1013200400026 |
oct | 152157732431 |
9 | 40715864761 |
10 | 14256420121 |
11 | 6056417499 |
12 | 291a543161 |
13 | 146278b868 |
14 | 99358454d |
15 | 5868d4731 |
hex | 351bfb519 |
14256420121 has 2 divisors, whose sum is σ = 14256420122. Its totient is φ = 14256420120.
The previous prime is 14256420109. The next prime is 14256420173. The reversal of 14256420121 is 12102465241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11413930896 + 2842489225 = 106836^2 + 53315^2 .
It is a cyclic number.
It is not a de Polignac number, because 14256420121 - 213 = 14256411929 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14256420121.
It is not a weakly prime, because it can be changed into another prime (14256421121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7128210060 + 7128210061.
It is an arithmetic number, because the mean of its divisors is an integer number (7128210061).
Almost surely, 214256420121 is an apocalyptic number.
It is an amenable number.
14256420121 is a deficient number, since it is larger than the sum of its proper divisors (1).
14256420121 is an equidigital number, since it uses as much as digits as its factorization.
14256420121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 14256420121 its reverse (12102465241), we get a palindrome (26358885362).
The spelling of 14256420121 in words is "fourteen billion, two hundred fifty-six million, four hundred twenty thousand, one hundred twenty-one".
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