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1425662301353 is a prime number
BaseRepresentation
bin10100101111110000000…
…110000101010010101001
312001021212212010202221112
4110233300012011102221
5141324224022120403
63010535030520105
7205000145421113
oct24576006052251
95037785122845
101425662301353
114aa690225104
121b0377506035
13a4593410584
144d0069163b3
15271410599d8
hex14bf01854a9

1425662301353 has 2 divisors, whose sum is σ = 1425662301354. Its totient is φ = 1425662301352.

The previous prime is 1425662301311. The next prime is 1425662301463. The reversal of 1425662301353 is 3531032665241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1373647288729 + 52015012624 = 1172027^2 + 228068^2 .

It is a cyclic number.

It is not a de Polignac number, because 1425662301353 - 220 = 1425661252777 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1425662301353.

It is not a weakly prime, because it can be changed into another prime (1425662301053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712831150676 + 712831150677.

It is an arithmetic number, because the mean of its divisors is an integer number (712831150677).

Almost surely, 21425662301353 is an apocalyptic number.

It is an amenable number.

1425662301353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1425662301353 is an equidigital number, since it uses as much as digits as its factorization.

1425662301353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 388800, while the sum is 41.

Adding to 1425662301353 its reverse (3531032665241), we get a palindrome (4956694966594).

The spelling of 1425662301353 in words is "one trillion, four hundred twenty-five billion, six hundred sixty-two million, three hundred one thousand, three hundred fifty-three".