Base | Representation |
---|---|
bin | 10000111111110… |
… | …01111010111001 |
3 | 100221021212221211 |
4 | 20133321322321 |
5 | 243000101213 |
6 | 22052003121 |
7 | 3350631211 |
oct | 1037717271 |
9 | 327255854 |
10 | 142581433 |
11 | 735355a5 |
12 | 3b9004a1 |
13 | 23702317 |
14 | 14d17241 |
15 | c7b653d |
hex | 87f9eb9 |
142581433 has 2 divisors, whose sum is σ = 142581434. Its totient is φ = 142581432.
The previous prime is 142581407. The next prime is 142581449. The reversal of 142581433 is 334185241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 91929744 + 50651689 = 9588^2 + 7117^2 .
It is a cyclic number.
It is not a de Polignac number, because 142581433 - 25 = 142581401 is a prime.
It is equal to p8049703 and since 142581433 and 8049703 have the same sum of digits, it is a Honaker prime.
It is a junction number, because it is equal to n+sod(n) for n = 142581395 and 142581404.
It is not a weakly prime, because it can be changed into another prime (142581403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71290716 + 71290717.
It is an arithmetic number, because the mean of its divisors is an integer number (71290717).
Almost surely, 2142581433 is an apocalyptic number.
It is an amenable number.
142581433 is a deficient number, since it is larger than the sum of its proper divisors (1).
142581433 is an equidigital number, since it uses as much as digits as its factorization.
142581433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11520, while the sum is 31.
The square root of 142581433 is about 11940.7467521927. The cubic root of 142581433 is about 522.4214397733.
The spelling of 142581433 in words is "one hundred forty-two million, five hundred eighty-one thousand, four hundred thirty-three".
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