Base | Representation |
---|---|
bin | 10100110000000111001… |
… | …111110010110110101001 |
3 | 12001022212221000122121101 |
4 | 110300013033302312221 |
5 | 141331022441120431 |
6 | 3011041344041401 |
7 | 205012603101334 |
oct | 24600717626651 |
9 | 5038787018541 |
10 | 1426050723241 |
11 | 4aa86a502231 |
12 | 1b0465603261 |
13 | a4625a29c01 |
14 | 4d04234561b |
15 | 271651d2961 |
hex | 14c073f2da9 |
1426050723241 has 2 divisors, whose sum is σ = 1426050723242. Its totient is φ = 1426050723240.
The previous prime is 1426050723187. The next prime is 1426050723277. The reversal of 1426050723241 is 1423270506241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1397055444841 + 28995278400 = 1181971^2 + 170280^2 .
It is a cyclic number.
It is not a de Polignac number, because 1426050723241 - 227 = 1425916505513 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1426050723241.
It is not a weakly prime, because it can be changed into another prime (1426050723641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 713025361620 + 713025361621.
It is an arithmetic number, because the mean of its divisors is an integer number (713025361621).
Almost surely, 21426050723241 is an apocalyptic number.
It is an amenable number.
1426050723241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1426050723241 is an equidigital number, since it uses as much as digits as its factorization.
1426050723241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 37.
The spelling of 1426050723241 in words is "one trillion, four hundred twenty-six billion, fifty million, seven hundred twenty-three thousand, two hundred forty-one".
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