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142611331 is a prime number
BaseRepresentation
bin10001000000000…
…01001110000011
3100221100101222011
420200001032003
5243002030311
622052353351
73351114322
oct1040011603
9327311864
10142611331
1173556005
123b915857
1323712b05
1414d240b9
15c7c0321
hex8801383

142611331 has 2 divisors, whose sum is σ = 142611332. Its totient is φ = 142611330.

The previous prime is 142611307. The next prime is 142611389. The reversal of 142611331 is 133116241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 142611331 - 211 = 142609283 is a prime.

It is a super-2 number, since 2×1426113312 = 40675983459183122, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (142612331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71305665 + 71305666.

It is an arithmetic number, because the mean of its divisors is an integer number (71305666).

Almost surely, 2142611331 is an apocalyptic number.

142611331 is a deficient number, since it is larger than the sum of its proper divisors (1).

142611331 is an equidigital number, since it uses as much as digits as its factorization.

142611331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 432, while the sum is 22.

The square root of 142611331 is about 11941.9986183218. The cubic root of 142611331 is about 522.4579528598.

Adding to 142611331 its reverse (133116241), we get a palindrome (275727572).

The spelling of 142611331 in words is "one hundred forty-two million, six hundred eleven thousand, three hundred thirty-one".