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14262130057 = 72037447151
BaseRepresentation
bin11010100100001011…
…01101010110001001
31100210221201021102011
431102011231112021
5213202101130212
610315114535521
71013300051050
oct152205552611
940727637364
1014262130057
11605966744a
1229204375a1
131463a0a816
1499422d397
155871614a7
hex35216d589

14262130057 has 4 divisors (see below), whose sum is σ = 16299577216. Its totient is φ = 12224682900.

The previous prime is 14262130033. The next prime is 14262130067. The reversal of 14262130057 is 75003126241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 75003126241 = 101037423847.

It is a cyclic number.

It is not a de Polignac number, because 14262130057 - 223 = 14253741449 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14262130067) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1018723569 + ... + 1018723582.

It is an arithmetic number, because the mean of its divisors is an integer number (4074894304).

Almost surely, 214262130057 is an apocalyptic number.

It is an amenable number.

14262130057 is a deficient number, since it is larger than the sum of its proper divisors (2037447159).

14262130057 is an equidigital number, since it uses as much as digits as its factorization.

14262130057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2037447158.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 14262130057 its reverse (75003126241), we get a palindrome (89265256298).

The spelling of 14262130057 in words is "fourteen billion, two hundred sixty-two million, one hundred thirty thousand, fifty-seven".

Divisors: 1 7 2037447151 14262130057