Base | Representation |
---|---|
bin | 10100110000101000011… |
… | …000000111000011001001 |
3 | 12001101022122220122021121 |
4 | 110300220120013003021 |
5 | 141333142234114431 |
6 | 3011212441235241 |
7 | 205032432415204 |
oct | 24605030070311 |
9 | 5041278818247 |
10 | 1426606551241 |
11 | 500025230013 |
12 | 1b059b792b21 |
13 | a46b3c2b011 |
14 | 4d0960b093b |
15 | 27198dc7611 |
hex | 14c286070c9 |
1426606551241 has 4 divisors (see below), whose sum is σ = 1426627181952. Its totient is φ = 1426585920532.
The previous prime is 1426606551221. The next prime is 1426606551257. The reversal of 1426606551241 is 1421556066241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1426606551241 - 237 = 1289167597769 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1426606551221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10211281 + ... + 10350046.
It is an arithmetic number, because the mean of its divisors is an integer number (356656795488).
Almost surely, 21426606551241 is an apocalyptic number.
It is an amenable number.
1426606551241 is a deficient number, since it is larger than the sum of its proper divisors (20630711).
1426606551241 is an equidigital number, since it uses as much as digits as its factorization.
1426606551241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20630710.
The product of its (nonzero) digits is 345600, while the sum is 43.
The spelling of 1426606551241 in words is "one trillion, four hundred twenty-six billion, six hundred six million, five hundred fifty-one thousand, two hundred forty-one".
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