Base | Representation |
---|---|
bin | 1100111111000001100110… |
… | …1001101011011111011001 |
3 | 1212112212011211020010210220 |
4 | 3033300121221223133121 |
5 | 3332403043310221340 |
6 | 50210415034230253 |
7 | 3002320634465010 |
oct | 317603151533731 |
9 | 55485154203726 |
10 | 14276901648345 |
11 | 4604888867466 |
12 | 1726b61585389 |
13 | 7c73c950924b |
14 | 3750119dda77 |
15 | 19b595820ed0 |
hex | cfc19a6b7d9 |
14276901648345 has 32 divisors (see below), whose sum is σ = 26359794020352. Its totient is φ = 6463218716352.
The previous prime is 14276901648343. The next prime is 14276901648403. The reversal of 14276901648345 is 54384610967241.
It is not a de Polignac number, because 14276901648345 - 21 = 14276901648343 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14276901648343) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 660040117 + ... + 660061746.
It is an arithmetic number, because the mean of its divisors is an integer number (823743563136).
It is a 1-persistent number, because it is pandigital, but 2⋅14276901648345 = 28553803296690 is not.
Almost surely, 214276901648345 is an apocalyptic number.
14276901648345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14276901648345 is a deficient number, since it is larger than the sum of its proper divisors (12082892372007).
14276901648345 is a wasteful number, since it uses less digits than its factorization.
14276901648345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1320101981.
The product of its (nonzero) digits is 34836480, while the sum is 60.
The spelling of 14276901648345 in words is "fourteen trillion, two hundred seventy-six billion, nine hundred one million, six hundred forty-eight thousand, three hundred forty-five".
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