Base | Representation |
---|---|
bin | 10100110010100110111… |
… | …100011110101011100001 |
3 | 12001120210122120202011111 |
4 | 110302212330132223201 |
5 | 141402014340430213 |
6 | 3012203254343321 |
7 | 205136155514041 |
oct | 24624674365341 |
9 | 5046718522144 |
10 | 1428730014433 |
11 | 500a14934377 |
12 | 1b0a9295ab41 |
13 | a4961b42707 |
14 | 4d218107721 |
15 | 27270526a3d |
hex | 14ca6f1eae1 |
1428730014433 has 2 divisors, whose sum is σ = 1428730014434. Its totient is φ = 1428730014432.
The previous prime is 1428730014421. The next prime is 1428730014497. The reversal of 1428730014433 is 3344100378241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1423423183329 + 5306831104 = 1193073^2 + 72848^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1428730014433 is a prime.
It is a super-2 number, since 2×14287300144332 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1428730018433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 714365007216 + 714365007217.
It is an arithmetic number, because the mean of its divisors is an integer number (714365007217).
Almost surely, 21428730014433 is an apocalyptic number.
It is an amenable number.
1428730014433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1428730014433 is an equidigital number, since it uses as much as digits as its factorization.
1428730014433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 193536, while the sum is 40.
The spelling of 1428730014433 in words is "one trillion, four hundred twenty-eight billion, seven hundred thirty million, fourteen thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •