1430011111201 has 4 divisors (see below), whose sum is σ = 1430013748804. Its totient is φ = 1430008473600.

The previous prime is 1430011111189. The next prime is 1430011111231. The reversal of 1430011111201 is 1021111100341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1219697151201 + 210313960000 = 1104399^2 + 458600^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1430011111201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1430011111231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 174720 + ... + 1700161.

It is an arithmetic number, because the mean of its divisors is an integer number (357503437201).

Almost surely, 2^{1430011111201} is an apocalyptic number.

It is an amenable number.

1430011111201 is a deficient number, since it is larger than the sum of its proper divisors (2637603).

1430011111201 is an equidigital number, since it uses as much as digits as its factorization.

1430011111201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2637602.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 1430011111201 its reverse (1021111100341), we get a palindrome (2451122211542).

The spelling of 1430011111201 in words is "one trillion, four hundred thirty billion, eleven million, one hundred eleven thousand, two hundred one".