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14300326483 is a prime number
BaseRepresentation
bin11010101000101110…
…11010101001010011
31100220121120212001121
431110113122221103
5213241340421413
610323001343111
71014242524642
oct152427325123
940817525047
1014300326483
116079185a43
122931197a97
13146b8c2461
14999333359
1558a6a8b8d
hex3545daa53

14300326483 has 2 divisors, whose sum is σ = 14300326484. Its totient is φ = 14300326482.

The previous prime is 14300326423. The next prime is 14300326501. The reversal of 14300326483 is 38462300341.

It is a strong prime.

It is an emirp because it is prime and its reverse (38462300341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14300326483 is a prime.

It is a super-2 number, since 2×143003264832 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14300326423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150163241 + 7150163242.

It is an arithmetic number, because the mean of its divisors is an integer number (7150163242).

Almost surely, 214300326483 is an apocalyptic number.

14300326483 is a deficient number, since it is larger than the sum of its proper divisors (1).

14300326483 is an equidigital number, since it uses as much as digits as its factorization.

14300326483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 34.

The spelling of 14300326483 in words is "fourteen billion, three hundred million, three hundred twenty-six thousand, four hundred eighty-three".