Base | Representation |
---|---|
bin | 10100110011111000101… |
… | …011010101011110100010 |
3 | 12001201100012210211111010 |
4 | 110303320223111132202 |
5 | 141412321410031002 |
6 | 3012551321001350 |
7 | 205215146034153 |
oct | 24637053253642 |
9 | 5051305724433 |
10 | 1430101252002 |
11 | 501558968465 |
12 | 1b11b6023256 |
13 | a4b1cc605a7 |
14 | 4d30828d92a |
15 | 27300ad946c |
hex | 14cf8ad57a2 |
1430101252002 has 32 divisors (see below), whose sum is σ = 2903915480832. Its totient is φ = 469419938064.
The previous prime is 1430101251991. The next prime is 1430101252049. The reversal of 1430101252002 is 2002521010341.
It is a self number, because there is not a number n which added to its sum of digits gives 1430101252002.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 517233 + ... + 1768539.
It is an arithmetic number, because the mean of its divisors is an integer number (90747358776).
Almost surely, 21430101252002 is an apocalyptic number.
1430101252002 is an abundant number, since it is smaller than the sum of its proper divisors (1473814228830).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1430101252002 is a wasteful number, since it uses less digits than its factorization.
1430101252002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1254222.
The product of its (nonzero) digits is 480, while the sum is 21.
Adding to 1430101252002 its reverse (2002521010341), we get a palindrome (3432622262343).
The spelling of 1430101252002 in words is "one trillion, four hundred thirty billion, one hundred one million, two hundred fifty-two thousand, two".
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