14301052041 has 8 divisors (see below), whose sum is σ = 19473773184. Its totient is φ = 9331182800.

The previous prime is 14301052039. The next prime is 14301052049. The reversal of 14301052041 is 14025010341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14301052041 - 2¹ = 14301052039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14301051999 and 14301052017.

It is not an unprimeable number, because it can be changed into a prime (14301052049) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50712810 + ... + 50713091.

It is an arithmetic number, because the mean of its divisors is an integer number (2434221648).

Almost surely, 2^14301052041 is an apocalyptic number.

It is an amenable number.

14301052041 is a deficient number, since it is larger than the sum of its proper divisors (5172721143).

14301052041 is a wasteful number, since it uses less digits than its factorization.

14301052041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101425951.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 14301052041 its reverse (14025010341), we get a palindrome (28326062382).

The spelling of 14301052041 in words is "fourteen billion, three hundred one million, fifty-two thousand, forty-one".