Base | Representation |
---|---|
bin | 11010101000111100… |
… | …10011010000101001 |
3 | 1100220201222112201111 |
4 | 31110132103100221 |
5 | 213242321144431 |
6 | 10323104150321 |
7 | 1014264052426 |
oct | 152436232051 |
9 | 40821875644 |
10 | 14302131241 |
11 | 607a1a8982 |
12 | 29319083a1 |
13 | 146c0a4a68 |
14 | 999682d4d |
15 | 58a9137b1 |
hex | 354793429 |
14302131241 has 2 divisors, whose sum is σ = 14302131242. Its totient is φ = 14302131240.
The previous prime is 14302131211. The next prime is 14302131257. The reversal of 14302131241 is 14213120341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11236848016 + 3065283225 = 106004^2 + 55365^2 .
It is a cyclic number.
It is not a de Polignac number, because 14302131241 - 25 = 14302131209 is a prime.
It is not a weakly prime, because it can be changed into another prime (14302131211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7151065620 + 7151065621.
It is an arithmetic number, because the mean of its divisors is an integer number (7151065621).
Almost surely, 214302131241 is an apocalyptic number.
It is an amenable number.
14302131241 is a deficient number, since it is larger than the sum of its proper divisors (1).
14302131241 is an equidigital number, since it uses as much as digits as its factorization.
14302131241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 14302131241 its reverse (14213120341), we get a palindrome (28515251582).
The spelling of 14302131241 in words is "fourteen billion, three hundred two million, one hundred thirty-one thousand, two hundred forty-one".
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