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14302305135411 = 312641377140657
BaseRepresentation
bin1101000000100000001111…
…0100010010101100110011
31212122021202020100222211020
43100020003310102230303
53333312110103313121
650230215511150523
73004210311533346
oct320100364225463
955567666328736
1014302305135411
114614634430277
12172ba71075443
137c99175052b7
143763417b845d
1519c080b451c6
hexd0203d12b33

14302305135411 has 8 divisors (see below), whose sum is σ = 19071248793744. Its totient is φ = 9534115783680.

The previous prime is 14302305135383. The next prime is 14302305135449. The reversal of 14302305135411 is 11453150320341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14302305135411 - 26 = 14302305135347 is a prime.

It is a super-2 number, since 2×143023051354112 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14302305135011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 188532406 + ... + 188608251.

It is an arithmetic number, because the mean of its divisors is an integer number (2383906099218).

Almost surely, 214302305135411 is an apocalyptic number.

14302305135411 is a deficient number, since it is larger than the sum of its proper divisors (4768943658333).

14302305135411 is a wasteful number, since it uses less digits than its factorization.

14302305135411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 377153301.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 14302305135411 its reverse (11453150320341), we get a palindrome (25755455455752).

The spelling of 14302305135411 in words is "fourteen trillion, three hundred two billion, three hundred five million, one hundred thirty-five thousand, four hundred eleven".

Divisors: 1 3 12641 37923 377140657 1131421971 4767435045137 14302305135411