Base | Representation |
---|---|
bin | 100000100001010000111101… |
… | …011010100110111010101001 |
3 | 200202101220111112112101012122 |
4 | 200201100331122212322221 |
5 | 122221244001440421441 |
6 | 1224104021211521025 |
7 | 42061050130462364 |
oct | 4041207532467251 |
9 | 622356445471178 |
10 | 143023441342121 |
11 | 416319a002a23a |
12 | 1405aa99159175 |
13 | 61a608b887732 |
14 | 274652b5590db |
15 | 118057bb6d34b |
hex | 82143d6a6ea9 |
143023441342121 has 2 divisors, whose sum is σ = 143023441342122. Its totient is φ = 143023441342120.
The previous prime is 143023441342109. The next prime is 143023441342139. The reversal of 143023441342121 is 121243144320341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 119933600016400 + 23089841325721 = 10951420^2 + 4805189^2 .
It is a cyclic number.
It is not a de Polignac number, because 143023441342121 - 222 = 143023437147817 is a prime.
It is not a weakly prime, because it can be changed into another prime (143023441342181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71511720671060 + 71511720671061.
It is an arithmetic number, because the mean of its divisors is an integer number (71511720671061).
Almost surely, 2143023441342121 is an apocalyptic number.
It is an amenable number.
143023441342121 is a deficient number, since it is larger than the sum of its proper divisors (1).
143023441342121 is an equidigital number, since it uses as much as digits as its factorization.
143023441342121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 143023441342121 its reverse (121243144320341), we get a palindrome (264266585662462).
The spelling of 143023441342121 in words is "one hundred forty-three trillion, twenty-three billion, four hundred forty-one million, three hundred forty-two thousand, one hundred twenty-one".
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