Base | Representation |
---|---|
bin | 10100110100000101001… |
… | …100100110110001110011 |
3 | 12001201212212001101110102 |
4 | 110310011030212301303 |
5 | 141413234143101321 |
6 | 3013024223023015 |
7 | 205223306311463 |
oct | 24640514466163 |
9 | 5051785041412 |
10 | 1430311300211 |
11 | 501656493822 |
12 | 1b125443aa6b |
13 | a4b54625381 |
14 | 4d328129ba3 |
15 | 2731427ac0b |
hex | 14d05326c73 |
1430311300211 has 2 divisors, whose sum is σ = 1430311300212. Its totient is φ = 1430311300210.
The previous prime is 1430311300183. The next prime is 1430311300247. The reversal of 1430311300211 is 1120031130341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1430311300211 - 214 = 1430311283827 is a prime.
It is a super-2 number, since 2×14303113002112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1430314300211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715155650105 + 715155650106.
It is an arithmetic number, because the mean of its divisors is an integer number (715155650106).
Almost surely, 21430311300211 is an apocalyptic number.
1430311300211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1430311300211 is an equidigital number, since it uses as much as digits as its factorization.
1430311300211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1430311300211 its reverse (1120031130341), we get a palindrome (2550342430552).
The spelling of 1430311300211 in words is "one trillion, four hundred thirty billion, three hundred eleven million, three hundred thousand, two hundred eleven".
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