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1430313164243 = 2835054110121
BaseRepresentation
bin10100110100000101010…
…011101101110111010011
312001201212222120002102122
4110310011103231313103
5141413240132223433
63013024331004455
7205223331204125
oct24640523556723
95051788502378
101430313164243
11501657547247
121b1254b9972b
13a4b54b28952
144d328493215
15273144e8198
hex14d054eddd3

1430313164243 has 4 divisors (see below), whose sum is σ = 1435367274648. Its totient is φ = 1425259053840.

The previous prime is 1430313164221. The next prime is 1430313164257. The reversal of 1430313164243 is 3424613130341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1430313164243 - 26 = 1430313164179 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1430313163243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2527054778 + ... + 2527055343.

It is an arithmetic number, because the mean of its divisors is an integer number (358841818662).

Almost surely, 21430313164243 is an apocalyptic number.

1430313164243 is a deficient number, since it is larger than the sum of its proper divisors (5054110405).

1430313164243 is an equidigital number, since it uses as much as digits as its factorization.

1430313164243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5054110404.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 1430313164243 its reverse (3424613130341), we get a palindrome (4854926294584).

The spelling of 1430313164243 in words is "one trillion, four hundred thirty billion, three hundred thirteen million, one hundred sixty-four thousand, two hundred forty-three".

Divisors: 1 283 5054110121 1430313164243