Base | Representation |
---|---|
bin | 1101000000100011100101… |
… | …1001001111100001000011 |
3 | 1212122101001212202202122021 |
4 | 3100020321121033201003 |
5 | 3333320430211423042 |
6 | 50230445021222311 |
7 | 3004241505062146 |
oct | 320107131174103 |
9 | 55571055682567 |
10 | 14303204014147 |
11 | 4614a55867164 |
12 | 1730082101997 |
13 | 7c9a2b7c84c9 |
14 | 3763c8d2205d |
15 | 19c0d49ee867 |
hex | d023964f843 |
14303204014147 has 2 divisors, whose sum is σ = 14303204014148. Its totient is φ = 14303204014146.
The previous prime is 14303204014139. The next prime is 14303204014189. The reversal of 14303204014147 is 74141040230341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14303204014147 - 23 = 14303204014139 is a prime.
It is a super-2 number, since 2×143032040141472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14303204014247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7151602007073 + 7151602007074.
It is an arithmetic number, because the mean of its divisors is an integer number (7151602007074).
Almost surely, 214303204014147 is an apocalyptic number.
14303204014147 is a deficient number, since it is larger than the sum of its proper divisors (1).
14303204014147 is an equidigital number, since it uses as much as digits as its factorization.
14303204014147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 34.
Adding to 14303204014147 its reverse (74141040230341), we get a palindrome (88444244244488).
The spelling of 14303204014147 in words is "fourteen trillion, three hundred three billion, two hundred four million, fourteen thousand, one hundred forty-seven".
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