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143032234239953 is a prime number
BaseRepresentation
bin100000100001011001001001…
…100000110110011111010001
3200202102202012022220212110022
4200201121021200312133101
5122221420003431134303
61224112033514113225
742061511050046132
oct4041311140663721
9622382168825408
10143032234239953
11416356a2427553
1214060731a1b815
1361a6b60464b66
142746b2325dc89
1511808e3a8b438
hex8216498367d1

143032234239953 has 2 divisors, whose sum is σ = 143032234239954. Its totient is φ = 143032234239952.

The previous prime is 143032234239941. The next prime is 143032234240013. The reversal of 143032234239953 is 359932432230341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129903735691024 + 13128498548929 = 11397532^2 + 3623327^2 .

It is a cyclic number.

It is not a de Polignac number, because 143032234239953 - 244 = 125440048195537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 143032234239895 and 143032234239904.

It is not a weakly prime, because it can be changed into another prime (143032234230953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71516117119976 + 71516117119977.

It is an arithmetic number, because the mean of its divisors is an integer number (71516117119977).

Almost surely, 2143032234239953 is an apocalyptic number.

It is an amenable number.

143032234239953 is a deficient number, since it is larger than the sum of its proper divisors (1).

143032234239953 is an equidigital number, since it uses as much as digits as its factorization.

143032234239953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12597120, while the sum is 53.

The spelling of 143032234239953 in words is "one hundred forty-three trillion, thirty-two billion, two hundred thirty-four million, two hundred thirty-nine thousand, nine hundred fifty-three".