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143033532113 = 276751692639
BaseRepresentation
bin1000010100110101110…
…1100111111011010001
3111200012020211021111102
42011031131213323101
54320413041011423
6145413024554145
713222334651153
oct2051535477321
9450166737442
10143033532113
115572977777a
1223879782955
13106461b7104
146ccc482ad3
153ac21dac28
hex214d767ed1

143033532113 has 4 divisors (see below), whose sum is σ = 143085227520. Its totient is φ = 142981836708.

The previous prime is 143033532023. The next prime is 143033532119. The reversal of 143033532113 is 311235330341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143033532113 - 212 = 143033528017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143033532119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25843553 + ... + 25849086.

It is an arithmetic number, because the mean of its divisors is an integer number (35771306880).

Almost surely, 2143033532113 is an apocalyptic number.

It is an amenable number.

143033532113 is a deficient number, since it is larger than the sum of its proper divisors (51695407).

143033532113 is an equidigital number, since it uses as much as digits as its factorization.

143033532113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51695406.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 143033532113 its reverse (311235330341), we get a palindrome (454268862454).

The spelling of 143033532113 in words is "one hundred forty-three billion, thirty-three million, five hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 2767 51692639 143033532113