Base | Representation |
---|---|
bin | 11010101001010011… |
… | …10000011101110011 |
3 | 1100220221122010100111 |
4 | 31110221300131303 |
5 | 213244103300301 |
6 | 10323252402151 |
7 | 1014331431226 |
oct | 152451603563 |
9 | 40827563314 |
10 | 14305134451 |
11 | 608096a273 |
12 | 2932916357 |
13 | 146c8b69ca |
14 | 999c255bd |
15 | 58ad08551 |
hex | 354a70773 |
14305134451 has 2 divisors, whose sum is σ = 14305134452. Its totient is φ = 14305134450.
The previous prime is 14305134439. The next prime is 14305134469. The reversal of 14305134451 is 15443150341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14305134451 - 27 = 14305134323 is a prime.
It is a super-2 number, since 2×143051344512 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14305134421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7152567225 + 7152567226.
It is an arithmetic number, because the mean of its divisors is an integer number (7152567226).
Almost surely, 214305134451 is an apocalyptic number.
14305134451 is a deficient number, since it is larger than the sum of its proper divisors (1).
14305134451 is an equidigital number, since it uses as much as digits as its factorization.
14305134451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 14305134451 its reverse (15443150341), we get a palindrome (29748284792).
The spelling of 14305134451 in words is "fourteen billion, three hundred five million, one hundred thirty-four thousand, four hundred fifty-one".
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