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1431011113 = 7967921121
BaseRepresentation
bin101010101001011…
…0111111100101001
310200201200220012121
41111102313330221
510412314323423
6353555311241
750314252030
oct12522677451
93621626177
101431011113
1167484a914
1233b2ab521
1319a618a4c
14d80a5717
158596d45d
hex554b7f29

1431011113 has 8 divisors (see below), whose sum is σ = 1635687680. Its totient is φ = 1226396160.

The previous prime is 1431011111. The next prime is 1431011123. The reversal of 1431011113 is 3111101341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1431011113 - 21 = 1431011111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1431011111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57193 + ... + 78313.

It is an arithmetic number, because the mean of its divisors is an integer number (204460960).

Almost surely, 21431011113 is an apocalyptic number.

It is an amenable number.

1431011113 is a deficient number, since it is larger than the sum of its proper divisors (204676567).

1431011113 is an equidigital number, since it uses as much as digits as its factorization.

1431011113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30807.

The product of its (nonzero) digits is 36, while the sum is 16.

The square root of 1431011113 is about 37828.7075248415. The cubic root of 1431011113 is about 1126.8886433520. Note that the first 3 decimals are identical.

Adding to 1431011113 its reverse (3111101341), we get a palindrome (4542112454).

The spelling of 1431011113 in words is "one billion, four hundred thirty-one million, eleven thousand, one hundred thirteen".

Divisors: 1 7 9679 21121 67753 147847 204430159 1431011113