Base | Representation |
---|---|
bin | 1101000000111101011110… |
… | …1001011101000110000011 |
3 | 1212200001000020110020010001 |
4 | 3100033113221131012003 |
5 | 3333424143413001431 |
6 | 50233554412220431 |
7 | 3004605646205323 |
oct | 320172751350603 |
9 | 55601006406101 |
10 | 14310154031491 |
11 | 46179a198204a |
12 | 17314a176a717 |
13 | 7ca598650bc6 |
14 | 376887d8b283 |
15 | 19c38ec43e61 |
hex | d03d7a5d183 |
14310154031491 has 2 divisors, whose sum is σ = 14310154031492. Its totient is φ = 14310154031490.
The previous prime is 14310154031471. The next prime is 14310154031507. The reversal of 14310154031491 is 19413045101341.
14310154031491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14310154031491 - 227 = 14310019813763 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14310154031491.
It is not a weakly prime, because it can be changed into another prime (14310154031471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155077015745 + 7155077015746.
It is an arithmetic number, because the mean of its divisors is an integer number (7155077015746).
Almost surely, 214310154031491 is an apocalyptic number.
14310154031491 is a deficient number, since it is larger than the sum of its proper divisors (1).
14310154031491 is an equidigital number, since it uses as much as digits as its factorization.
14310154031491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 37.
The spelling of 14310154031491 in words is "fourteen trillion, three hundred ten billion, one hundred fifty-four million, thirty-one thousand, four hundred ninety-one".
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