Base | Representation |
---|---|
bin | 1101000000111101101001… |
… | …1001111101111000011001 |
3 | 1212200001010110112001212102 |
4 | 3100033122121331320121 |
5 | 3333424242234200004 |
6 | 50234003144053145 |
7 | 3004610050414133 |
oct | 320173231757031 |
9 | 55601113461772 |
10 | 14310200303129 |
11 | 4617a16006675 |
12 | 17314b51641b5 |
13 | 7ca5a5102283 |
14 | 376890194053 |
15 | 19c393d3411e |
hex | d03da67de19 |
14310200303129 has 2 divisors, whose sum is σ = 14310200303130. Its totient is φ = 14310200303128.
The previous prime is 14310200303053. The next prime is 14310200303137. The reversal of 14310200303129 is 92130300201341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11960807233600 + 2349393069529 = 3458440^2 + 1532773^2 .
It is an emirp because it is prime and its reverse (92130300201341) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14310200303129 is a prime.
It is not a weakly prime, because it can be changed into another prime (14310200303629) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155100151564 + 7155100151565.
It is an arithmetic number, because the mean of its divisors is an integer number (7155100151565).
Almost surely, 214310200303129 is an apocalyptic number.
It is an amenable number.
14310200303129 is a deficient number, since it is larger than the sum of its proper divisors (1).
14310200303129 is an equidigital number, since it uses as much as digits as its factorization.
14310200303129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 29.
The spelling of 14310200303129 in words is "fourteen trillion, three hundred ten billion, two hundred million, three hundred three thousand, one hundred twenty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.102 sec. • engine limits •