143102040132 has 96 divisors (see below), whose sum is σ = 350629171200. Its totient is φ = 45362396800.

The previous prime is 143102040127. The next prime is 143102040163. The reversal of 143102040132 is 231040201341.

It is a junction number, because it is equal to n+sod(n) for n = 143102040099 and 143102040108.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32587657 + ... + 32592047.

It is an arithmetic number, because the mean of its divisors is an integer number (3652387200).

Almost surely, 2^143102040132 is an apocalyptic number.

143102040132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 143102040132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (175314585600).

143102040132 is an abundant number, since it is smaller than the sum of its proper divisors (207527131068).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143102040132 is a wasteful number, since it uses less digits than its factorization.

143102040132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5817 (or 5815 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 143102040132 its reverse (231040201341), we get a palindrome (374142241473).

The spelling of 143102040132 in words is "one hundred forty-three billion, one hundred two million, forty thousand, one hundred thirty-two".