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143103221011 is a prime number
BaseRepresentation
bin1000010101000110011…
…1011101110100010011
3111200101002221211200201
42011101213131310103
54321033411033021
6145423554400031
713224142210612
oct2052147356423
9450332854621
10143103221011
1155765046003
1223898b90017
131065777714a
146cd7823879
153ac83a4591
hex21519ddd13

143103221011 has 2 divisors, whose sum is σ = 143103221012. Its totient is φ = 143103221010.

The previous prime is 143103220999. The next prime is 143103221069. The reversal of 143103221011 is 110122301341.

143103221011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 143103221011 - 223 = 143094832403 is a prime.

It is a super-2 number, since 2×1431032210112 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 143103221011.

It is not a weakly prime, because it can be changed into another prime (143103228011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71551610505 + 71551610506.

It is an arithmetic number, because the mean of its divisors is an integer number (71551610506).

Almost surely, 2143103221011 is an apocalyptic number.

143103221011 is a deficient number, since it is larger than the sum of its proper divisors (1).

143103221011 is an equidigital number, since it uses as much as digits as its factorization.

143103221011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 143103221011 its reverse (110122301341), we get a palindrome (253225522352).

The spelling of 143103221011 in words is "one hundred forty-three billion, one hundred three million, two hundred twenty-one thousand, eleven".