Search a number
-
+
143103514123 = 1300911000347
BaseRepresentation
bin1000010101000110100…
…0100101011000001011
3111200101010111201202201
42011101220211120023
54321033444422443
6145424004541031
713224144541303
oct2052150453013
9450333451681
10143103514123
1155765226249
12238990b1777
131065784a69b
146cd789c603
153ac841134d
hex2151a2560b

143103514123 has 4 divisors (see below), whose sum is σ = 143114527480. Its totient is φ = 143092500768.

The previous prime is 143103514111. The next prime is 143103514153. The reversal of 143103514123 is 321415301341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143103514123 - 217 = 143103383051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143103514091 and 143103514100.

It is not an unprimeable number, because it can be changed into a prime (143103514153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5487165 + ... + 5513182.

It is an arithmetic number, because the mean of its divisors is an integer number (35778631870).

Almost surely, 2143103514123 is an apocalyptic number.

143103514123 is a deficient number, since it is larger than the sum of its proper divisors (11013357).

143103514123 is a wasteful number, since it uses less digits than its factorization.

143103514123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11013356.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 143103514123 its reverse (321415301341), we get a palindrome (464518815464).

The spelling of 143103514123 in words is "one hundred forty-three billion, one hundred three million, five hundred fourteen thousand, one hundred twenty-three".

Divisors: 1 13009 11000347 143103514123