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14310894383561 is a prime number
BaseRepresentation
bin1101000001000000001111…
…0001101011000111001001
31212200002220211120000020002
43100100003301223013021
53333432202430233221
650234200100412345
73004633206122216
oct320200361530711
955602824500202
1014310894383561
114618241882566
1217316696a70b5
137ca685b4b159
1437691842ab0d
1519c3d4c3780b
hexd0403c6b1c9

14310894383561 has 2 divisors, whose sum is σ = 14310894383562. Its totient is φ = 14310894383560.

The previous prime is 14310894383501. The next prime is 14310894383609. The reversal of 14310894383561 is 16538349801341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12419499305161 + 1891395078400 = 3524131^2 + 1375280^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14310894383561 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14310894383497 and 14310894383506.

It is not a weakly prime, because it can be changed into another prime (14310894383501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155447191780 + 7155447191781.

It is an arithmetic number, because the mean of its divisors is an integer number (7155447191781).

Almost surely, 214310894383561 is an apocalyptic number.

It is an amenable number.

14310894383561 is a deficient number, since it is larger than the sum of its proper divisors (1).

14310894383561 is an equidigital number, since it uses as much as digits as its factorization.

14310894383561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7464960, while the sum is 56.

The spelling of 14310894383561 in words is "fourteen trillion, three hundred ten billion, eight hundred ninety-four million, three hundred eighty-three thousand, five hundred sixty-one".