Base | Representation |
---|---|
bin | 1000010101001000000… |
… | …1001101100110011011 |
3 | 111200101120122202000112 |
4 | 2011102001031212123 |
5 | 4321042123022311 |
6 | 145424355154535 |
7 | 13224253451126 |
oct | 2052201154633 |
9 | 450346582015 |
10 | 143109970331 |
11 | 55768935959 |
12 | 2389b2a5a4b |
13 | 10658c9b223 |
14 | 6cd869d3bd |
15 | 3ac8c8928b |
hex | 215204d99b |
143109970331 has 2 divisors, whose sum is σ = 143109970332. Its totient is φ = 143109970330.
The previous prime is 143109970313. The next prime is 143109970337. The reversal of 143109970331 is 133079901341.
Together with previous prime (143109970313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143109970331 - 222 = 143105776027 is a prime.
It is a super-2 number, since 2×1431099703312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (143109970337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71554985165 + 71554985166.
It is an arithmetic number, because the mean of its divisors is an integer number (71554985166).
Almost surely, 2143109970331 is an apocalyptic number.
143109970331 is a deficient number, since it is larger than the sum of its proper divisors (1).
143109970331 is an equidigital number, since it uses as much as digits as its factorization.
143109970331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 41.
The spelling of 143109970331 in words is "one hundred forty-three billion, one hundred nine million, nine hundred seventy thousand, three hundred thirty-one".
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