Base | Representation |
---|---|
bin | 10100110100110101000… |
… | …001100110111011111010 |
3 | 12001210221202221201110202 |
4 | 110310311001212323322 |
5 | 141421410103124032 |
6 | 3013240005442202 |
7 | 205252221640421 |
oct | 24646501467372 |
9 | 5053852851422 |
10 | 1431113723642 |
11 | 501a2842a389 |
12 | 1b1439110362 |
13 | a4c51946335 |
14 | 4d3a29262b8 |
15 | 2735e930d62 |
hex | 14d35066efa |
1431113723642 has 4 divisors (see below), whose sum is σ = 2146670585466. Its totient is φ = 715556861820.
The previous prime is 1431113723623. The next prime is 1431113723657. The reversal of 1431113723642 is 2463273111341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1048164392401 + 382949331241 = 1023799^2 + 618829^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1431113723596 and 1431113723605.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 357778430909 + ... + 357778430912.
Almost surely, 21431113723642 is an apocalyptic number.
1431113723642 is a deficient number, since it is larger than the sum of its proper divisors (715556861824).
1431113723642 is an equidigital number, since it uses as much as digits as its factorization.
1431113723642 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 715556861823.
The product of its digits is 72576, while the sum is 38.
Adding to 1431113723642 its reverse (2463273111341), we get a palindrome (3894386834983).
The spelling of 1431113723642 in words is "one trillion, four hundred thirty-one billion, one hundred thirteen million, seven hundred twenty-three thousand, six hundred forty-two".
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