143111441331 has 8 divisors (see below), whose sum is σ = 212016950160. Its totient is φ = 95407627536.

The previous prime is 143111441329. The next prime is 143111441371. The reversal of 143111441331 is 133144111341.

143111441331 is a `hidden beast` number, since 1 + 4 + 311 + 14 + 4 + 1 + 331 = 666.

It is not a de Polignac number, because 143111441331 - 2¹ = 143111441329 is a prime.

It is a super-2 number, since 2×143111441331² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 5300423753 = 143111441331 / (1 + 4 + 3 + 1 + 1 + 1 + 4 + 4 + 1 + 3 + 3 + 1).

It is a junction number, because it is equal to n+sod(n) for n = 143111441295 and 143111441304.

It is not an unprimeable number, because it can be changed into a prime (143111441371) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2650211850 + ... + 2650211903.

It is an arithmetic number, because the mean of its divisors is an integer number (26502118770).

Almost surely, 2^143111441331 is an apocalyptic number.

143111441331 is a deficient number, since it is larger than the sum of its proper divisors (68905508829).

143111441331 is an equidigital number, since it uses as much as digits as its factorization.

143111441331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5300423762 (or 5300423756 counting only the distinct ones).

The product of its digits is 1728, while the sum is 27.

Adding to 143111441331 its reverse (133144111341), we get a palindrome (276255552672).

The spelling of 143111441331 in words is "one hundred forty-three billion, one hundred eleven million, four hundred forty-one thousand, three hundred thirty-one".