Base | Representation |
---|---|
bin | 11010101010000001… |
… | …11100100001001001 |
3 | 1100221101001221201201 |
4 | 31111000330201021 |
5 | 213302132310004 |
6 | 10324030544201 |
7 | 1014434206303 |
oct | 152500744111 |
9 | 40841057651 |
10 | 14311213129 |
11 | 6084341274 |
12 | 2934968061 |
13 | 1470c34765 |
14 | 99a968973 |
15 | 58b6096a4 |
hex | 35503c849 |
14311213129 has 4 divisors (see below), whose sum is σ = 14396909184. Its totient is φ = 14225517076.
The previous prime is 14311213123. The next prime is 14311213153. The reversal of 14311213129 is 92131211341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14311213129 - 225 = 14277658697 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14311213097 and 14311213106.
It is not an unprimeable number, because it can be changed into a prime (14311213123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42847777 + ... + 42848110.
It is an arithmetic number, because the mean of its divisors is an integer number (3599227296).
Almost surely, 214311213129 is an apocalyptic number.
It is an amenable number.
14311213129 is a deficient number, since it is larger than the sum of its proper divisors (85696055).
14311213129 is an equidigital number, since it uses as much as digits as its factorization.
14311213129 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85696054.
The product of its digits is 1296, while the sum is 28.
The spelling of 14311213129 in words is "fourteen billion, three hundred eleven million, two hundred thirteen thousand, one hundred twenty-nine".
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